高中數(shù)學(xué) 第一章 不等式的基本性質(zhì)和證明的基本方法 1.5.1 比較法課件 新人教B版選修45

《高中數(shù)學(xué) 第一章 不等式的基本性質(zhì)和證明的基本方法 1.5.1 比較法課件 新人教B版選修45》由會員分享，可在線閱讀，更多相關(guān)《高中數(shù)學(xué) 第一章 不等式的基本性質(zhì)和證明的基本方法 1.5.1 比較法課件 新人教B版選修45（21頁珍藏版）》請?jiān)谘b配圖網(wǎng)上搜索。

1、1 1.5 5不等式證明的基本方法不等式證明的基本方法1 1.5 5.1 1比較法目標(biāo)導(dǎo)航DIANLITOUXI典例透析SUITANGLIANXI隨堂演練ZHONGNANJUJIAO重難聚焦ZHISHISHULI知識梳理目標(biāo)導(dǎo)航DIANLITOUXI典例透析SUITANGLIANXI隨堂演練ZHONGNANJUJIAO重難聚焦ZHISHISHULI知識梳理目標(biāo)導(dǎo)航DIANLITOUXI典例透析SUITANGLIANXI隨堂演練ZHONGNANJUJIAO重難聚焦ZHISHISHULI知識梳理目標(biāo)導(dǎo)航DIANLITOUXI典例透析SUITANGLIANXI隨堂演練ZHONGNANJUJIAO重難

2、聚焦ZHISHISHULI知識梳理DIANLITOUXI典例透析SUITANGLIANXI隨堂演練ZHONGNANJUJIAO重難聚焦ZHISHISHULI知識梳理目標(biāo)導(dǎo)航1.理解和掌握比較法證明不等式的依據(jù).2.掌握利用比較法證明不等式的一般步驟.3.通過學(xué)習(xí)比較法證明不等式,培養(yǎng)學(xué)生對轉(zhuǎn)化思想的理解和應(yīng)用.目標(biāo)導(dǎo)航DIANLITOUXI典例透析SUITANGLIANXI隨堂演練ZHONGNANJUJIAO重難聚焦ZHISHISHULI知識梳理目標(biāo)導(dǎo)航DIANLITOUXI典例透析SUITANGLIANXI隨堂演練ZHONGNANJUJIAO重難聚焦ZHISHISHULI知識梳理目標(biāo)導(dǎo)航DI

3、ANLITOUXI典例透析SUITANGLIANXI隨堂演練ZHONGNANJUJIAO重難聚焦ZHISHISHULI知識梳理目標(biāo)導(dǎo)航DIANLITOUXI典例透析SUITANGLIANXI隨堂演練ZHONGNANJUJIAO重難聚焦ZHISHISHULI知識梳理DIANLITOUXI典例透析SUITANGLIANXI隨堂演練ZHONGNANJUJIAO重難聚焦ZHISHISHULI知識梳理目標(biāo)導(dǎo)航比較法證明不等式可分為作差比較法和作商比較法兩種 目標(biāo)導(dǎo)航DIANLITOUXI典例透析SUITANGLIANXI隨堂演練ZHONGNANJUJIAO重難聚焦ZHISHISHULI知識梳理目標(biāo)導(dǎo)航D

4、IANLITOUXI典例透析SUITANGLIANXI隨堂演練ZHONGNANJUJIAO重難聚焦ZHISHISHULI知識梳理目標(biāo)導(dǎo)航DIANLITOUXI典例透析SUITANGLIANXI隨堂演練ZHONGNANJUJIAO重難聚焦ZHISHISHULI知識梳理目標(biāo)導(dǎo)航DIANLITOUXI典例透析SUITANGLIANXI隨堂演練ZHONGNANJUJIAO重難聚焦ZHISHISHULI知識梳理DIANLITOUXI典例透析SUITANGLIANXI隨堂演練ZHONGNANJUJIAO重難聚焦ZHISHISHULI知識梳理目標(biāo)導(dǎo)航【做一做1】 設(shè)m=a+2b,n=a+b2+1,則()A.

5、mnB.mnC.mbc0,求證:a2ab2bc2cab+cbc+aca+b.分析:證明這類含冪指數(shù)乘積形式的不等式,往往通過作商與1比較大小來證明.證明:由abc0,得ac+bbc+aca+b0.所證不等式左邊除以右邊,得目標(biāo)導(dǎo)航DIANLITOUXI典例透析SUITANGLIANXI隨堂演練ZHONGNANJUJIAO重難聚焦ZHISHISHULI知識梳理目標(biāo)導(dǎo)航DIANLITOUXI典例透析SUITANGLIANXI隨堂演練ZHONGNANJUJIAO重難聚焦ZHISHISHULI知識梳理目標(biāo)導(dǎo)航DIANLITOUXI典例透析SUITANGLIANXI隨堂演練ZHONGNANJUJIAO重

6、難聚焦ZHISHISHULI知識梳理目標(biāo)導(dǎo)航DIANLITOUXI典例透析SUITANGLIANXI隨堂演練ZHONGNANJUJIAO重難聚焦ZHISHISHULI知識梳理DIANLITOUXI典例透析SUITANGLIANXI隨堂演練ZHONGNANJUJIAO重難聚焦ZHISHISHULI知識梳理目標(biāo)導(dǎo)航題型一題型二題型四題型三反思證明此題易出現(xiàn)在不討論ab+cbc+aca+b0的前提下,就開始作商;或在未得到a-b0, ,就得出商大于1,這些都是解題不嚴(yán)謹(jǐn)?shù)谋憩F(xiàn),解題時(shí)要注意這一點(diǎn).一般地,要比較的兩個(gè)解析式均為正值時(shí),可利用作商的方法比較其大小,如果兩個(gè)解析式均為負(fù)值時(shí),可用同樣的方

7、法比較其絕對值的大小.目標(biāo)導(dǎo)航DIANLITOUXI典例透析SUITANGLIANXI隨堂演練ZHONGNANJUJIAO重難聚焦ZHISHISHULI知識梳理目標(biāo)導(dǎo)航DIANLITOUXI典例透析SUITANGLIANXI隨堂演練ZHONGNANJUJIAO重難聚焦ZHISHISHULI知識梳理目標(biāo)導(dǎo)航DIANLITOUXI典例透析SUITANGLIANXI隨堂演練ZHONGNANJUJIAO重難聚焦ZHISHISHULI知識梳理目標(biāo)導(dǎo)航DIANLITOUXI典例透析SUITANGLIANXI隨堂演練ZHONGNANJUJIAO重難聚焦ZHISHISHULI知識梳理DIANLITOUXI典例

8、透析SUITANGLIANXI隨堂演練ZHONGNANJUJIAO重難聚焦ZHISHISHULI知識梳理目標(biāo)導(dǎo)航題型一題型二題型三題型四比較法的實(shí)際應(yīng)用【例3】 已知買8千克胡蘿卜和10千克白菜的錢小于22元,而買12千克胡蘿卜和6千克白菜的錢大于24元,問買2千克胡蘿卜與3千克白菜的錢哪個(gè)更多些?分析:設(shè)每千克胡蘿卜和每千克白菜的錢分別為a元和b元,根據(jù)條件列出a,b間的關(guān)系式,比較2a與3b的大小即可.目標(biāo)導(dǎo)航DIANLITOUXI典例透析SUITANGLIANXI隨堂演練ZHONGNANJUJIAO重難聚焦ZHISHISHULI知識梳理目標(biāo)導(dǎo)航DIANLITOUXI典例透析SUITANG

9、LIANXI隨堂演練ZHONGNANJUJIAO重難聚焦ZHISHISHULI知識梳理目標(biāo)導(dǎo)航DIANLITOUXI典例透析SUITANGLIANXI隨堂演練ZHONGNANJUJIAO重難聚焦ZHISHISHULI知識梳理目標(biāo)導(dǎo)航DIANLITOUXI典例透析SUITANGLIANXI隨堂演練ZHONGNANJUJIAO重難聚焦ZHISHISHULI知識梳理DIANLITOUXI典例透析SUITANGLIANXI隨堂演練ZHONGNANJUJIAO重難聚焦ZHISHISHULI知識梳理目標(biāo)導(dǎo)航題型一題型二題型三題型四反思應(yīng)用不等式解決實(shí)際問題時(shí),關(guān)鍵是如何把等量關(guān)系、不等量關(guān)系轉(zhuǎn)化為不等式的

10、問題來解決.在實(shí)際應(yīng)用不等關(guān)系問題時(shí),常用比較法來判斷數(shù)的大小關(guān)系,若是選擇題或填空題,則可用特殊值加以判斷.目標(biāo)導(dǎo)航DIANLITOUXI典例透析SUITANGLIANXI隨堂演練ZHONGNANJUJIAO重難聚焦ZHISHISHULI知識梳理目標(biāo)導(dǎo)航DIANLITOUXI典例透析SUITANGLIANXI隨堂演練ZHONGNANJUJIAO重難聚焦ZHISHISHULI知識梳理目標(biāo)導(dǎo)航DIANLITOUXI典例透析SUITANGLIANXI隨堂演練ZHONGNANJUJIAO重難聚焦ZHISHISHULI知識梳理目標(biāo)導(dǎo)航DIANLITOUXI典例透析SUITANGLIANXI隨堂演練ZH

11、ONGNANJUJIAO重難聚焦ZHISHISHULI知識梳理DIANLITOUXI典例透析SUITANGLIANXI隨堂演練ZHONGNANJUJIAO重難聚焦ZHISHISHULI知識梳理目標(biāo)導(dǎo)航題型一題型二題型三題型四易錯(cuò)辨析易錯(cuò)點(diǎn):作差后對差式變形不恰當(dāng),使判斷符號的過程含糊不清.【例4】 判斷函數(shù)f(x)=x3在R上的單調(diào)性.錯(cuò)解:設(shè)x1,x2是R上的任意兩個(gè)數(shù),且x1f(x1).f(x)=x3在R上為增函數(shù).目標(biāo)導(dǎo)航DIANLITOUXI典例透析SUITANGLIANXI隨堂演練ZHONGNANJUJIAO重難聚焦ZHISHISHULI知識梳理目標(biāo)導(dǎo)航DIANLITOUXI典例透析

12、SUITANGLIANXI隨堂演練ZHONGNANJUJIAO重難聚焦ZHISHISHULI知識梳理目標(biāo)導(dǎo)航DIANLITOUXI典例透析SUITANGLIANXI隨堂演練ZHONGNANJUJIAO重難聚焦ZHISHISHULI知識梳理目標(biāo)導(dǎo)航DIANLITOUXI典例透析SUITANGLIANXI隨堂演練ZHONGNANJUJIAO重難聚焦ZHISHISHULI知識梳理DIANLITOUXI典例透析SUITANGLIANXI隨堂演練ZHONGNANJUJIAO重難聚焦ZHISHISHULI知識梳理目標(biāo)導(dǎo)航題型一題型二題型三題型四目標(biāo)導(dǎo)航DIANLITOUXI典例透析SUITANGLIANX

13、I隨堂演練ZHONGNANJUJIAO重難聚焦ZHISHISHULI知識梳理目標(biāo)導(dǎo)航DIANLITOUXI典例透析SUITANGLIANXI隨堂演練ZHONGNANJUJIAO重難聚焦ZHISHISHULI知識梳理目標(biāo)導(dǎo)航DIANLITOUXI典例透析SUITANGLIANXI隨堂演練ZHONGNANJUJIAO重難聚焦ZHISHISHULI知識梳理目標(biāo)導(dǎo)航DIANLITOUXI典例透析SUITANGLIANXI隨堂演練ZHONGNANJUJIAO重難聚焦ZHISHISHULI知識梳理DIANLITOUXI典例透析SUITANGLIANXI隨堂演練ZHONGNANJUJIAO重難聚焦ZHISHISHULI知識梳理目標(biāo)導(dǎo)航1 2 3 4 51下列關(guān)系式中對任意ab0,且a1,P=loga(a3+1),Q=loga(a2+1),則P,Q的大小關(guān)系是()A.PQ B.PQ B.P0,故(x+1)(x2-x+1)(x-1)(x2+x+1).答案: